During class, Dr. Eviatar did some things about right triangles. So I think that's what i'm putting here. Just notify me if there's something wrong. So good luck guys and take a look at it!! :P

So Let's see.... Here's the one she did.

**SIN A/a = SIN B/b = SIN C/c**

**Angle B = 72°**

Angle C = 67°

Angle C = 67°

**b = 42**

**c = ?**

**b/SIN B = c/SIN C**

**42/SIN 72̲̲̲̲̱̱̱̱̲̲̲̲̱̱̱̱° = C/SIN 67°**

**(42) (SIN67°/SIN72°)**

So it will be...

**(42)(SIN67°) = 36.5**

After that... Do this like :

**36.5/SIN72°**

So the answer will be...

**c = 40.3**

There you have it.

Oh,, Finally... I almost forgot, there's a homework that Mrs. Eviatar wants us to finish.

Homework

**(Exercise 19 # 2-6, 17)**

2.

2.

Find The Value of X.

3.

3.

**Find b.**

**4.**

**Find a.**

**5.**

Find Angle A.

**6.**

Find Angle B

**.**

**17. The school flagpole is 14m high. A student measures the angle of elevation of the top of the pole to be 31°. She then moves closer to the pole and finds the angle of elevation has increased to 48°. Find the distance that she moved from the first measurement to the second.**

**___________________________________________________**

**Alright!! Finally I'm done.... Take a look at those and check if there's something wrong... Good luck to all of you guys!!.. :)**

**SO I THINK THE NEXT BLOGGER WILL BE AKEEM NOW!!!**

**YOUR THE ONE WHO'S NEXT HAHAHAHAH!! :P**

**HOPE YOU DO IT!!**

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